Integrand size = 26, antiderivative size = 69 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {(b d-a e) (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 b^2}+\frac {e \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{5 b^2} \]
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Time = 0.01 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {654, 623} \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {(a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} (b d-a e)}{4 b^2}+\frac {e \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{5 b^2} \]
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Rule 623
Rule 654
Rubi steps \begin{align*} \text {integral}& = \frac {e \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{5 b^2}+\frac {\left (2 b^2 d-2 a b e\right ) \int \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx}{2 b^2} \\ & = \frac {(b d-a e) (a+b x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{4 b^2}+\frac {e \left (a^2+2 a b x+b^2 x^2\right )^{5/2}}{5 b^2} \\ \end{align*}
Time = 1.02 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.20 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {x \sqrt {(a+b x)^2} \left (10 a^3 (2 d+e x)+10 a^2 b x (3 d+2 e x)+5 a b^2 x^2 (4 d+3 e x)+b^3 x^3 (5 d+4 e x)\right )}{20 (a+b x)} \]
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Time = 3.07 (sec) , antiderivative size = 90, normalized size of antiderivative = 1.30
method | result | size |
gosper | \(\frac {x \left (4 b^{3} e \,x^{4}+15 a \,b^{2} e \,x^{3}+5 b^{3} d \,x^{3}+20 a^{2} b e \,x^{2}+20 a \,b^{2} d \,x^{2}+10 a^{3} e x +30 a^{2} b d x +20 a^{3} d \right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{20 \left (b x +a \right )^{3}}\) | \(90\) |
default | \(\frac {x \left (4 b^{3} e \,x^{4}+15 a \,b^{2} e \,x^{3}+5 b^{3} d \,x^{3}+20 a^{2} b e \,x^{2}+20 a \,b^{2} d \,x^{2}+10 a^{3} e x +30 a^{2} b d x +20 a^{3} d \right ) \left (\left (b x +a \right )^{2}\right )^{\frac {3}{2}}}{20 \left (b x +a \right )^{3}}\) | \(90\) |
risch | \(\frac {\sqrt {\left (b x +a \right )^{2}}\, b^{3} e \,x^{5}}{5 b x +5 a}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (3 a \,b^{2} e +b^{3} d \right ) x^{4}}{4 b x +4 a}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (3 a^{2} b e +3 a \,b^{2} d \right ) x^{3}}{3 b x +3 a}+\frac {\sqrt {\left (b x +a \right )^{2}}\, \left (e \,a^{3}+3 d \,a^{2} b \right ) x^{2}}{2 b x +2 a}+\frac {\sqrt {\left (b x +a \right )^{2}}\, a^{3} d x}{b x +a}\) | \(153\) |
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none
Time = 0.27 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.00 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {1}{5} \, b^{3} e x^{5} + a^{3} d x + \frac {1}{4} \, {\left (b^{3} d + 3 \, a b^{2} e\right )} x^{4} + {\left (a b^{2} d + a^{2} b e\right )} x^{3} + \frac {1}{2} \, {\left (3 \, a^{2} b d + a^{3} e\right )} x^{2} \]
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Leaf count of result is larger than twice the leaf count of optimal. 745 vs. \(2 (65) = 130\).
Time = 0.71 (sec) , antiderivative size = 745, normalized size of antiderivative = 10.80 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\begin {cases} \sqrt {a^{2} + 2 a b x + b^{2} x^{2}} \left (\frac {b^{2} e x^{4}}{5} + \frac {x^{3} \cdot \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b^{2}} + \frac {x^{2} \cdot \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b^{2}} + \frac {x \left (4 a^{3} b e + 6 a^{2} b^{2} d - \frac {3 a^{2} \cdot \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b^{2}} - \frac {5 a \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b}\right )}{2 b^{2}} + \frac {a^{4} e + 4 a^{3} b d - \frac {2 a^{2} \cdot \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b^{2}} - \frac {3 a \left (4 a^{3} b e + 6 a^{2} b^{2} d - \frac {3 a^{2} \cdot \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b^{2}} - \frac {5 a \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b}\right )}{2 b}}{b^{2}}\right ) + \frac {\left (\frac {a}{b} + x\right ) \left (a^{4} d - \frac {a^{2} \cdot \left (4 a^{3} b e + 6 a^{2} b^{2} d - \frac {3 a^{2} \cdot \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b^{2}} - \frac {5 a \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b}\right )}{2 b^{2}} - \frac {a \left (a^{4} e + 4 a^{3} b d - \frac {2 a^{2} \cdot \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b^{2}} - \frac {3 a \left (4 a^{3} b e + 6 a^{2} b^{2} d - \frac {3 a^{2} \cdot \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b^{2}} - \frac {5 a \left (\frac {26 a^{2} b^{2} e}{5} + 4 a b^{3} d - \frac {7 a \left (\frac {11 a b^{3} e}{5} + b^{4} d\right )}{4 b}\right )}{3 b}\right )}{2 b}\right )}{b}\right ) \log {\left (\frac {a}{b} + x \right )}}{\sqrt {b^{2} \left (\frac {a}{b} + x\right )^{2}}} & \text {for}\: b^{2} \neq 0 \\\frac {\frac {\left (a^{2} + 2 a b x\right )^{\frac {5}{2}} \left (- a e + 2 b d\right )}{10 b} + \frac {e \left (a^{2} + 2 a b x\right )^{\frac {7}{2}}}{14 a b}}{a b} & \text {for}\: a b \neq 0 \\\left (d x + \frac {e x^{2}}{2}\right ) \left (a^{2}\right )^{\frac {3}{2}} & \text {otherwise} \end {cases} \]
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Leaf count of result is larger than twice the leaf count of optimal. 125 vs. \(2 (61) = 122\).
Time = 0.20 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.81 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {1}{4} \, {\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} d x - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} a e x}{4 \, b} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} a d}{4 \, b} - \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {3}{2}} a^{2} e}{4 \, b^{2}} + \frac {{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac {5}{2}} e}{5 \, b^{2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 145 vs. \(2 (61) = 122\).
Time = 0.27 (sec) , antiderivative size = 145, normalized size of antiderivative = 2.10 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {1}{5} \, b^{3} e x^{5} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{4} \, b^{3} d x^{4} \mathrm {sgn}\left (b x + a\right ) + \frac {3}{4} \, a b^{2} e x^{4} \mathrm {sgn}\left (b x + a\right ) + a b^{2} d x^{3} \mathrm {sgn}\left (b x + a\right ) + a^{2} b e x^{3} \mathrm {sgn}\left (b x + a\right ) + \frac {3}{2} \, a^{2} b d x^{2} \mathrm {sgn}\left (b x + a\right ) + \frac {1}{2} \, a^{3} e x^{2} \mathrm {sgn}\left (b x + a\right ) + a^{3} d x \mathrm {sgn}\left (b x + a\right ) + \frac {{\left (5 \, a^{4} b d - a^{5} e\right )} \mathrm {sgn}\left (b x + a\right )}{20 \, b^{2}} \]
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Time = 9.90 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.61 \[ \int (d+e x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2} \, dx=\frac {\left (a+b\,x\right )\,\left (5\,b\,d-a\,e+4\,b\,e\,x\right )\,{\left (a^2+2\,a\,b\,x+b^2\,x^2\right )}^{3/2}}{20\,b^2} \]
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